# RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data

Here you can get solutions of RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data. These Solutions are part of RS Aggarwal Solutions Class 10. we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data download pdf.

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### Exercise 9A

Question 1:
Table is as given below:

Question 2:
We have

Question 3:
We have

Question 4:
We have

Question 5:
We have

Mean,
Question 6:
We have

Mean,
Question 7:
We have

Question 8:
We have

Question 9:
We have

Question 10:
We have, Let A = 25 be the assumed mean

Hence mean = 28.
Question 11:
A = 100 be the assumed mean, we have

Hence, mean = 110.67
Question 12:
Let the assumed mean be 150, h = 20

Hence, Mean = 146.25
Question 13:
Let A = 50 be the assumed mean, we have

Question 14:

We have h = 10 and let assumed mean = 25.
A = 25, h = 10, ∑ fi= 100 and ∑(fi×ui)= 30

Hence the mean of given frequency distribution is 28.
Question 15:
We have h = 4 and let assumed mean be A = 26. We have the table given below:

A = 26, h = 4, ∑ fi= 100 and ∑(fi×ui)= -152

Hence the mean of given frequency distribution is 19.92.
Question 16:
We have h= 30 and let A = 75 be the assumed mean. we have the table given below:

Thus, A = 75, h = 30, ∑ fi= 150 and ∑(fi×ui)= 80

Hence, the mean of the given frequency distribution is 91.
Question 17:
We ahve h = 20 and let A = 70 be the assumed mean. We have the table given below:

Thus, A = 70, h = 20, ∑ fi= 120 and ∑(fi×ui)= -4

Hence the mean of given frequency distribution is 69.33.
Question 18:
We have h = 14 and let A = 35 be the assumed mean.
For calculating the mean, we prepare the table given below:

Thus, A = 35, ∑ fi= 90, h = 14 and ∑(fi×ui)= 8

Hence, Mean = 36.24
Question 19:
Let h = 5 and let A = 22.5 be the assumed mean.
For calculating the mean, we prepare the table given below:

Thus, A = 22.5 and h = 5
∑ fi= 40 and   ∑(fi×ui)= 17

Hence the mean of given frequency distribution is 24.625.
Question 20:
We have h = 6 and let assume mean A = 33. For calculating the mean we prepare the table.

Thus, A = 33, h = 6, ∑ fi= 40 and ∑(fi×ui)=2

Hence, Mean = 33.3 years
Question 21:
We have h = 6 and let assumed mean A = 99. For calculating the mean we prepare the table:

Thus, A = 99, h = 6 and ∑ fi= 120, ∑(fi×ui)=2

Hence, Mean = 103.05.
Question 22:
Let h = 20 and assume mean = 550, we prepare the table given below:

Thus, A = 550, h = 20, and ∑ fi= 40, ∑(fi×ui)=-12

Hence the mean of the frequency distribution is 544.
Question 23:
The given series is an inclusive series, making it an exclusive series, we have

Thus, A = 42, h = 5, ∑ fi= 70 and ∑(fi×ui)=-37

Hence, Mean = 39.36 years.
Question 24:
The given series is an inclusive series making it an exclusive series, we get

Thus, A = 29.5, h = 10, ∑ fi= 80 and ∑(fi×ui)=43

Hence, Mean = 34.87 years.

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