RD Sharma Solutions for Class 8 Chapter 24 Data Handling

In this chapter, we provide RD Sharma Solutions for Class 8 Chapter 24 Data Handling for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Class 8 Chapter 24 Data Handling pdf, free RD Sharma Solutions for Class 8 Chapter 24 Data Handling book pdf download. Now you will get step by step solution to each question.

Access answers to RD Sharma Class 8 Maths Solutions for Chapter 24 Data Handling – II (Graphical Representation of Data as Histogram)

1. Given below is the frequency distribution of the heights of 50 students of a class:

Class Interval140 – 145145 – 150150 – 155155 – 160160 – 165
Frequency81218105

Draw a histogram representing the above data.

Solution:

The class limits are represented along the x-axis on a suitable scale and the frequencies are represented along the y-axis on a suitable scale. Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be constructed to obtain the histogram of the given frequency distribution as shown in the figure below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 1

2. Draw a histogram of the following data:

Class Interval10 – 1515 – 2020 – 2525 – 3030 – 3535 – 40
Frequency309880582950

Solution:

The class limits are represented along the x-axis and the frequencies are represented along the y-axis on a suitable scale. Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be drawn to obtain the histogram of the given frequency distribution. The histogram is shown below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 2

3. Number of workshops organized by a school in different areas during the last five years are as follows:

YearsNo: of Workshops
1995 – 199625
1996 – 199730
1997 – 199842
1998 – 199950
1999 – 200065

Draw a histogram representing the above data:

Solution:

The class limits are represented along the x-axis and the frequencies are represented along the y-axis on a suitable scale. Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be constructed to obtain histogram for the given frequency. The histogram is shown below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 3

4. In a hypothetical sample of 20 people the amounts of money with them were found to be as follows:
114, 108, 100, 98, 101, 109, 117, 119, 126, 131, 136, 143, 156, 168, 182, 195, 207, 219, 235, 118.
Draw the histogram of the frequency distribution (taking one of the class intervals as 50-100).

Solution:

We first prepare the frequency table for the class intervals 50−100, 100−150,…, 200−250, as shown below:

Class IntervalFrequency
50 – 1002
100 – 15011
150 – 2004
200 – 2503

The class limits are represented along the x-axis and the frequencies along the y-axis on a suitable scale. Taking the class intervals as bases and the corresponding frequencies as heights, the rectangles can be drawn to obtain the histogram of the given frequency distribution. The histogram is shown below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 4

5. Construct a histogram for the following data:

Monthly School Fee(in Rs)30-6060-9090-120120-150150-180180-210210-240
No: of Schools51214181094

Solution:

The class limits are represented along the x-axis and the frequencies along the y-axis on a suitable scale. Taking class intervals as bases and corresponding frequencies as heights of the rectangles, the histogram of the given data can be obtained as shown in the figure below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 5

6. Draw a histogram for the daily earnings of 30 drug stores in the following table:

Daily Earnings(in Rs)450 – 500500 – 550550 – 600600 – 650650 – 700
No: of Stores1610731

Solution:

The class limits are represented along the x-axis and the frequencies along the y-axis on a suitable scale. Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be drawn to obtain the histogram of the given frequency distribution. The histogram is given below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 6

7. Draw a histogram to represent the following data:

Monthly Salary (in Rs)No: of Teachers
5600 – 57008
5700 – 58004
5800 – 59003
5900 – 60005
6000 – 61002
6100 – 62003
6200 – 63001
6300 – 64002

Solution:

Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be constructed to obtain the histogram of the given data. The class intervals are represented along the x-axis and the frequencies along the y-axis on a suitable scale.

The histogram representing the given data is shown below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 7

8. The following histogram shows the number of literate females in the age group of 10 to 40 years in a town:

(i) Write the age group in which the number of literate female is the highest.
(ii) What is the class width?
(iii) What is the lowest frequency?
(iv) What are the class marks of the classes?
(v) In which age group literate females are the least?

Solution:

(i) The highest rectangle corresponds to the highest number of literate females, which is in the interval 15−20 years.

(ii) The class intervals are 10−15, 15−20, 20−25, 30−35, 35−40. Hence, the class width is 5.

(iii) The lowest rectangle corresponds to the lowest frequency, which is 320.

(iv) The class mark is the mid-point of the class interval.

i.e., Class mark = (upper limit + lower limit) / 2

Hence, the class mark of each class is as follows:

Class IntervalClass Marks
10 – 1512.5
15 – 2017.5
20 – 2522.5
25 – 3027.5
30 – 3532.5
35 – 4037.5

(v) The lowest rectangle corresponds to the least number of literate females, which is in the interval 10−15 years.

9. The following histogram shows the monthly wages (in Rs) of workers in a factory:

(i) In which wage-group the largest numbers of worders are being kept? What is their number?
(ii) What wages are the least number of workers getting? What is the number of such workers?
(iii) What is the total number of workers?
(iv) What is the factory size?

Solution:

(i) From the figure, the highest rectangle corresponds to the largest number of workers. The required interval is Rs 950−1000. There are 8 workers in this interval.

(ii) The lowest rectangle corresponds to the least number of workers. The required interval is Rs 900−950. There are 2 workers in this interval.

(iii) The total number of workers is the sum of workers in all the intervals. It can be calculated as follows:

Total workers = 3 + 7 + 5 + 4 + 2 + 8 + 6 + 5 = 40 workers

(iv) The factory intervals are 750−800, 800−850, .. 1050−100. Hence, the factory size is 50.

10. Below is the histogram depicting marks obtained by 43 students of a class:
(i) Write the number of students getting the highest marks.
(ii) What is the class size?

Solution:

(i) In the given histogram, the interval with the highest marks is 90−100.

Three students are there in this interval because the height of the rectangle (90−100) is 3 units.

(ii) The class intervals are 10−20, 20−30, …, 90−100. So, the class size is 10.

11. The following histogram shows the frequency distribution of the ages of 22 teachers in a school:

(i) What is the number of eldest and youngest teachers in the school?
(ii) Which age group teachers are more in the school and which least?
(iii) What is the size of the classes?
(iv) What are the class marks of the classes?

Solution:

(i) The eldest (50−55 years) = 1 person

This is because the height of the rectangle with class interval 50−55 as base is 1 unit.

The youngest (20−25 years) = 2 persons

This is because the height of the rectangle with class interval 20−25 as base is 2 units.

(ii) The group containing the most number of teachers is 35−40 years. This is because the height of the rectangle with class interval 35−40 as base is the maximum.

The group containing the least number of teachers is 50−55 years. This is because the height of the rectangle with class interval 50−55 as base is the minimum.

(iii) Class size = The range between the upper and the lower boundaries of the class

For example, the size of the class 20−25 years is 5.

(iv) The class mark is the mid-point of the class interval.

i.e., Class mark = (upper limit + lower limit) / 2

Hence, the class mark of each class is as follows:

For Class 20 – 25:

Class mark = (20+25)/2 = 45/2 = 22.5

Similarly, the class marks of the other classes are 27.5, 32.5, 37.5, 42.5, 47.5, 52.5.

12. The weekly wages (in Rs.) of 30 workers in a factory are given:
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840
Mark a frequency table with intervals as 800-810, 810-820 and so on, using tally marks.
Also, draw a histogram and answer the following questions:
(i) Which group has the maximum number of workers?
(ii) How many workers earn Rs. 850 and more?
(iii) How many workers earn less then Rs, 850?

Solution:

The frequency table with intervals 800−820, 810−820,…890−900 is shown below:

Wages (in Rs)Frequency
800 – 8104
810 – 8202
820 – 8301
830 – 84011
840 – 8502
850 – 8602
860 – 8702
870 – 8801
880 – 8904
890 – 9001

The class limits are represented along the x-axis and the frequencies along the y-axis on a suitable scale. Taking class intervals as bases and the corresponding frequencies as heights, the rectangles can be drawn to obtain the histogram of the given frequency distribution. The histogram is shown below:

RD Sharma Solutions for Class 8 Maths Chapter 24 – Data Handling – II (Graphical Representation of Data as Histograms) image - 12

(i) The group that has the maximum number of workers is represented as the highest rectangle. It is in the interval 830−840.

(ii) The number of workers who earn Rs 850 or more can be calculated from frequency table in the following manner:

1 + 3 + 1 + 1 + 4 = 101 + 3 + 1 + 1 + 4 = 10

(iii) The number of workers who earn less than Rs 850 can be calculated from frequency table in the following manner:

3 + 2 + 1 + 9 + 5 = 203 + 2 + 1 + 9 + 5 = 20


All Chapter RD Sharma Solutions For Class 8 Maths

*************************************************

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.

If these solutions have helped you, you can also share alarity.in to your friends.

Leave a Comment

Your email address will not be published. Required fields are marked *